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import acm.graphics.*; import acm.program.*; import java.awt.*;
Here is the correct Python code using the Turtle module to solve this problem. 9.1.7 Checkerboard V2 Codehs
, which determines if a row or column index is even or odd. A standard checkerboard pattern follows these rules: Even rows (0, 2, 4, 6) : Start with [0, 1, 0, 1, 0, 1, 0, 1] Odd rows (1, 3, 5, 7) : Start with [1, 0, 1, 0, 1, 0, 1, 0] Step-by-Step Implementation Initialize the Grid Create an empty list (often named ) to hold the rows of your checkerboard. Outer Loop for Rows loop to iterate through the 8 rows of the board. Alternating Row Logic Within the outer loop, check if the current row index is even or odd: i % 2 == 0 : Append a row where elements alternate starting with : Append a row where elements alternate starting with Nested Loop Method (Alternative) import acm
You must use nested loops and assignment statements to modify an existing grid of zeros. 💻 Implementation (Python) Outer Loop for Rows loop to iterate through
/* This program draws a full checkerboard on the screen. * It uses a constant for square size to make it dynamic. */ var SQUARE_SIZE = 40; function start() // Calculate how many rows and columns fit on the screen var rows = getHeight() / SQUARE_SIZE; var cols = getWidth() / SQUARE_SIZE; for(var r = 0; r < rows; r++) for(var c = 0; c < cols; c++) drawSquare(r, c); function drawSquare(row, col) var x = col * SQUARE_SIZE; var y = row * SQUARE_SIZE; var rect = new Rectangle(SQUARE_SIZE, SQUARE_SIZE); rect.setPosition(x, y); // The magic logic: if the sum of row and col is even, it's red if((row + col) % 2 == 0) rect.setColor(Color.red); else rect.setColor(Color.black); add(rect); Use code with caution. Copied to clipboard Pro-Tips for Success